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? 2M 3.M An object of mass 3M, moving in the +x direction at speed Do, breaks into two pieces of mass M and 2M as shown in th
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Answer #1

So we use conservation of linear momentum in horizontal and vertical direction so we write

in horizontal direction

3Mv_0= 2Mv_2cos\theta_2+Mv_1cos\theta_1

3v_0= 2v_2cos\theta_2+v_1cos\theta_1

and in vertical directon

0= 2Mv_2sin\theta_2-Mv_1sin\theta_1

so

2v_2sin\theta_2=v_1sin\theta_1

so, plug in value we get

v_2=1.17v_1

so using this in 1st eqiuation

we get

v_1= 1.17v_0

and using this

v_2= 1.37v_0

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