Question

MY NUMBER IS 201772052 , SO YOU WILL MULTIPLY IT WITH 100

5.1 MPa pressure and 500 oC temperature and x m/s air enters a turbine. 150 kPa pressure rises at 150 oC temperature and 250m/s speed. Since the sectional area is 80 square centimeters; (x is the percentage of each student's number based on the last digit. For example, for 20171061 it is 100 °C. If your number is greater than 3, multiply by 10.) a. Mass flow of air b. The power produced by the turbine c. Find the adiabatic efficiency of the turbine.

Answer 1

5.1) Ans) Assumption :o c) This is a steady flow process since there is no change with time b) Potential energy changes are negligible c) Heat tronsfer is negligible gan As with Constant 0 d) Air is an ideal Specific heat poopestios:- The Constant Specific threat of air is Cp = 1:00 ks/ kg Ratio of specific feat, K=1140 Density of Air = 1.225 kg/m3 Analysis.per mpa, 1,3500c, V,= 200 m/s Air Pa = 150kpq, ty 5150's, V=250m's

And sectional Area 80 cm2 al Mass flow of Air (m) There is o only one inlet and one Assume exit exit . Thus, m = mia= mi Suppose sectional area of infet =gocm m = SAVO Is Density of air AT Area at inter Vt Velocity at infot m = (1.225*60 X10-4 m2)x 200 m/s kg/m3

m; = m = m = 1.96 kg/s And Mom flow of air=1.9. 1.95kgls b)' The power produced by the tushine + We toke turbine as the System which is a control volume since mos crosse the boundary. The energy balance for this steady system can be exprewed in the fore foomis Ein = Eout =) m (hty? 2000 2000 Wourt M (h2 + V2 ² where, Ih= ks/ kg 2 mi (Cpti Wourt mi (setzt f 2000 2000 2 + V2² & Wout 2000 =) 1.96 [C, (T-72) + V, ² vz? kg/s .961915 [100 kyky(500:15) 200u i 069/ lag /500-150°C + 2002-2 502 = Wout

> Wout = 663.956.18 = 663.95kW Ang V power developed by turnine (iii) Adiab mbatic Efficiency of turbine. Adiabati stic Work mi Cp (Ti-T2 K = specific kal heot Ratio=1.9 96 kg/s X1'000 Kylieg x 500-250 1.4-1 =1715KW Wolk =(( Adiabatic Adiabatic Efficiency Actual Work 4dia batre Work 6 63.95kW 0.38 Ang 1715 Kw He ha Adiabatic Efficiency = 0.38 tuthine of