Use the residue theorem to compute the next definite integral

please don't skip any steps and answer thoroughly

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Use the residue theorem to compute the next definite integral please don't skip any steps and...
A. Express the limit as a definite integral on the given
interval.
B. Use the form of the definition of the integral to evaluate
the integral.
n Š lim n-> Xi Ax, [1, 3] (xi +13 * 2 i=1 3 6 (2x - x2) dx
step by step please, thank
you
(2) Use Stokes' Theorem to evaluate the integral F.dr, where F(x, y, z) =< -Y, I, z > and where S is the upper hemispherical surface defined by z = v1- 2 - y2. The boundary of S is the curve C defined by Cos (t) y= sin (t) 0t 27 Z=0
please prove part (b) use complex analysis and calculus of
residue
-dx neif a> 0 5. (a) x2+1 (b) For any real number a > 0, cos x dx ne"/a. a Hint: This is the real part of the integral obtained by replacing cos x by e
Problem 4: Use the surface integral in Stokes' theorem to evaluate F.dr for the hemisphere S : x2 + y2 + z2 = 9; z > 0, its bounding circle C: 2+9 and the field F-yi- xj. You only have to compute the surface integral, not the line integral. (20 points)
write legibly please!!
9. Evaluate the following definite integrals (1) >> 23 - 3x2 + 5da (2) Si cos xdx 4
1 9. Find the principal value of dc 25 +1 COS ac 10. Find the principal value of dr, a > 0, b>0. (.x2 +62)2
Show Sketch and all steps.
Problem 18 Use the Divergence Theorem to calculate the surface integral || FdS , F(x,y,z) =< x²yz,xy-z, xyz? > S is the surface of the box enclosed by the planes x = 0, x = a, y = 0, y = b, z = 0, and z = C, where a, b, c are positive numbers.
use residue theorem to evaluate the following
integrals
sin z 21) 20) Cosx dx (r? + 1) X 22) sin mx dx 2(x² + a²² (a > 0, b>0) 23) cos ex - cos bx -dx x?
1. Let F(x,y,z) =< 32, 5x, – 2y >. Use Stokes's Theorem to evaluate the integral Scurl F.ds, where S is the part of the paraboloid z = x² + y2 that lies below the plane z = 4 with upward- pointing normal vector.
Evaluate the following integral using residues: I = { cos(bx)-cos(ax) dx. x2 Let a and b: real constants such that a > b>0. Note: cos(bz)-cos(az) is well-behaved along the real axis (singularity at z = 0 is removable), ejbz-ejaz has a pole at the origin. Make sure to handle this point correctly 22