A 100 mg technetium-99 sample is used in a medical study. How much of the technetium-99...

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A 100 mg technetium-99 sample is used in a medical study. How much of the technetium-99 sample remains after 24 hr? The half-

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Answer 1

Answer #1

K = 0.693 / T1/2

= 0.693 / 6.0

= 0.1155 hr-1

ln ( initial amount / final amount ) = K * time

ln ( 100 / final amount ) = 0.1155 * 24

= 6.25 mg

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Answer 2

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