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How many grams of dry NH4Cl need to be added to 1.90 L of a 0.800...

How many grams of dry NH4Cl need to be added to 1.90 L of a 0.800 M solution of ammonia, NH3, to prepare a buffer solution that has a pH of 8.74? Kb for ammonia is 1.8×10^−5. Express your answer with the appropriate units.

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weak base = NH3 salt - NH4CI Volume = 1.90 L NH3 = 0.800 M Kb = 1.8x10-5 pH = 8.74 molar mass of NH4CI = 53.49 g/mol NH4Cl =] calculating concentration: According to Henderson-Hasselbalch equation salt pOH = pKb + log ( weak base ] NH4Cl pOH = pKb +

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