Question

The Department of Inland Fisheries and Game did a survey of ice fishing shacks last winter. A random sample of 195 shacks on the Kennebec River found that 152 had some type of heat source. On the Eastern River, a sample of 162 shacks found that 118 had some type of heat.

a. what are the null and alternative hypotheses?

b. At alpha = 0.05 does this indicate that the proportions are different on the two rivers?

c. How does this compare with the result in #3?

Answer 1

118 ni 72 PP .7795-17284 Rvalue = P112131.1196] Because of two-tailed of p-value is greater than 2 (level of significanco Scletion 96 n=195, 2= 152 12 = 162, da 7795 than samproportion Pr = 2 = 152 195 & sample proportion P = d2 17284 a combined estimate 6) = x1 + x2 = 152+118 270 nitha 195+162 357 75 63 Ho & P = P2 USHIP, IP2 6 to test Above Apoth at £2.05 we proceed as below 27 þ.bz JFeltit .7563X (4.7563) 2-stat 6511 ·00208289 104564 2-stat 1.1196 hypothesis = Q P {27 1.11961 = 28.1314 12620 Here pe value is greater than 2 = 105 so we fail to repectro hwe have not sufficient evidence that proportion are different Result can be campared value 17563XC7 63) (tastro 0511 PP p-value E c using k h 18 p-value is less than a then Reject no