Question

18:48 ? < Inorganic Chemistry 10... c) multiple proportions d) definite proportions 10. A gas occupies a volume of 300 cm at a pressure of 103.97 kPa and at a temperature of 47°C. What volume would the gas occupy at standard conditions? 249.4 cm b) 262,7 cm c) 342,6 cm d) 360,9 cm 11. In an analytical determination, 520 cm- of hydrogen was collected and confined over water. The barometric pressure was 99,97 kPa, and the temperature was 27°C. What was the volume of hydrogen corrected to standard conditions? a) 450.3 cm b) 497,2 cm c) 546,8 cm d) 600,4 cm Inorganic Chemistry / CICG / Page 73 12. 100 dm of gas at 25°C is compressed to 75 dm. What will be the new temperature to maintain a constant pressure? a) -49.5C b) 124.30 c) 223,50 d) 397,3 C 13. At a pressure of 103.97 kPa, agus occupies 150 dm'. What volume will the gas occupy if the pressure is reduced by 6,665 kPa, but the temperature remains constant? a) 139,3 dm b) 140,4 dm c) 160,3 dm d) 161.5 dm c 14. A gas occupies a volume of 280 dm at a pressure of 101,3 kPa and at a temperature of 27°C. What will the pressure be if the gas is compressed to 260 dm and held at a temperature of -3°C? a) 84.6 kPa b) 98.18 kPa c) 109,1 kPa d) 121,2 kPa 15. The burning of coal is an example of III 0

Answer 1

Some unit conversions are used.

1 litre = 1000 ml

1 cm3= 1ml

1 atm = 101325 pascal

T(k)=T(°C)+ 273

R is ideal gas constant= 0.0821 litre-atm/mole-kelvin

* Volume of 1 mole has at standard Condition= 22.4 litre.

(10 Volume va cm3 300 cm V = 0.30L 1 cm3 10-3L Pressure p = 103.97 kPa = 103.97X103 Pa P= 1.026 atm I atm - 101325 Pa 3२०८ Tem berature T = 47°C = ideal gas equation pv=nRTI n 10.0821) X320 17.026) (0.30) = na 0.0117 mole Ni- Volume of I mole at standard conditiens = 22.42 & Volume of 0.0117male = 0.0117X74.41 = 0.26272 262.7 cm 3 Ans (b) 302.7 cm3 520 340 cm cm3 -0.52L volume of I mole = 22.44 pa 99.97 X Paz 0.9866 afm ... Volume of 0.0208 male T- 27°C = 300k -0.0208X2-4 Puan RT ~ 4 0.460L 0.9866X0.52 an (0.0821) (300) = 4 60 cm? Any A) 450,3 CM cm3 n = 0.0208 mole CS Scanned with CamScanner