here,
the resistivity of copper , p = 1.7 * 10^-8 ohm.m
length of wire , l = 2 m
cross-sectional area , A = 1 * 10^-4 m^2
potential difference , V = 20 V
the current in the wire , I = V /R
I = V /(p * l /A)
I = 20 /( 1.7 * 10^-8 * 2 /(1 * 10^-4)) A
I = 5.88 * 10^4 A
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A long, straight, copper wire with a circular cross-sectional
are of 1.5mmm^2 carries a current of 3 A
.
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question 2,7,9 please
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