Question

Prove the equation in the black box how it became like the green box

J-WL um R? + WL)? l'lt). Rum Cos/wt) + WL Um 2 (اسما) + 22 Sinlu (ا + 22 = I'm Cos/who o-tan (R2 L) 2 المعادلة يلي بالبوكس الاسود بدك تثبت او توضح كيف صار شكلها زي المعادلة بالبوکس الاخضر بتستخدم متطابقات مثلثة 4:36 PM

Answer 1

Q Rum wh um sinwt. ... iLt) - Coscot + R²7 (w.)? R²7 (w.)? Solve This should know the formula . To B Cos CA-B) = COS A COSB + sin A sing to Cos(A-B) format det me change eq- اما sinwt. X R X ป) coswt t VRF (W) VRF (W) um VRE (6) ilt) - R²+ (why? اما Vm R îlt) Coswt X + R7 (WL)² R761); sincot 1/0 VRE (ww.)? sina SinB 72 COSA Cosb In اما R sinB COSB = from comparing R²7 (w.)? ✓ R7 (why? sinB from Triangle concept. Tam B= Tand COSB B=4 = Tan -IOL R COL دو سال COL Vertwy Tam B= Tomo B=0 R/ VREI (6) R &= Tañ with i ilt)= Im [ co Coswt cos + sinut sind Answer Im Cos (wt-p From (B ilt) COL There fore taken 16 -Tan R But in your Answer 1 -Tan WL ĈLt) - Im Cos(wt + ) where pe R Im = ~ Rt (why?