Question

what are 17 and 18?

Question 17 (10 points) A constant current is passed through a solution of Agt in an electrolytic cell. In 3.0 minutes, 0.65 g of silver is deposited at the cathode. The number of moles of electrons passed into the Agt solution is mole. (Please enter your answer in decimal form, such as 0.021, and keep 2 significant figures.) The total coulombs of charge passed into the Cu2+ solution is C. (Please enter your answer in decimal form, such as 230, and keep 2 significant figures.) The current in amps used is A. (Please enter your answer in decimal form, such as 5.0, and keep 2 significant figures.)

Answer 1

I number moles Dogg Agt deposited on cathode as Ag. number of gram equivalent of metal deposited & number of Faraday of charge passed. q elections passed. 108 g factor for Ag=1 number of moles = 0.65 q gm equivalent = number q moles xn-factor of Mag g 108 number 0.65 10B x -0.006gm, equivalen number of gm. equi. no. moles - 0006 electrons number of moles q electons passed of q I mole electrono = 1 Faraday charge - 96500 C 0.006 mole electrons = 0.006 X 96500 C 579 Coulomb charge Current a charge (coulomb) time (second) ampere 3 minutes a 3x60 see = 180 see cument = 579 C 180 sec = 3,2166 Amper current = 3,22A