Question

Given: Uso kao To fps Empo 1300 K=5 lblin. WA10165 WB = 15165 Find: a) the max compression of the spring b) max height reached by A at the rebound c) Energy lost due to the collision Do this for e=0

Answer 1

д Dato Pago Sol". 2 от е fume ppeo » Friction force =0 12.85 1/+ a tо льд с Giren VA= 10 ft/sec Keseblin WA=to 165 WBT в (S 2, 3 0 me maximum compression of the spring Sino ЈА WACOSO MAG = WA (1-ms 4 Let compression е spring & x By work Energy theorem Wo sin 0x (20+x) + Wo sino x x = Tқу- дуу, रे Я а) 10 гъ30х (ю+x) + S %30-х = x 60 x x - - Т. 10 х 10- I WAX VA 32:2. Ә) 100 – 5х+ 2.5 х 30х-- S. S279

Data Page. 100 + 205 x = 30x²15.5279 D 30x²_215x 115,5279 =0 By 1x=2 ft Answer solving ey maximum I'm height reached by A at the rebound. * coefficient of Restitution eco Hence collesion in plastic, After collession both block A & B moving with same velocity Honce By Energy conservation Potential energy of spring I Potential Energy of Blocks (Both A $03 5 Ika² MAJH + Magh 2 - Xbox 2 ² = (WA + WB) H (10+15) H IH 120 - H = 120 = 4.8 ft 25 maximum Height Answers

② present here there is no friction force (11=0) Hence the loss in total Energy will be Zero