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20) In the circuit below, the current (I)) is going into the node (located under R,), current (12) is going into the node (lo
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* Answer! R2 RI Ra n +) Na ET ar * Apply Ki UiL in loop-] Vit 9R1+ (1, -2, JRs = 0 I 2 R2 + V₂ + (22-I, J Rs =0 = (R+R) I, -* Determinand can be found as (RIAA R3 det CA) Rat R3 Rather) -R3 a 2 ) Jerca) = (Rut Rg. ). (R2 +83) - R3 =) dea (A) = RioRa22 = N, Rg - V2 CR1 + Rs) R. R2 & R2 - Rst Rs. R1 so current in Rg is Ig 23 -- 20, R3 -242 R3 ~ V2 Ri TV, R2 RiRet Re: Rg tQgThanks please rate it up.

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