Question

An array antenna consists of two identical half-wave dipole antenna elements. The array operates in air at 100 MHz. User A is in the azimuth plane of the array, on a line that makes 60° with the line defined by the antenna elements. The driving current has no phase shift. What is the shortest physical distance, d, between the antenna elements in the array that will ensure maximum signal strength in the direction of the user? I lew 600 d

Answer 1

Array factor of the given array of 2 antennes will be sin (29) een (2 den ( AF din (4) where 4 = k dosa + 4 and 4 phase difference b/w the two elements: Now what we want us that mosuma occurs @ O = 60° and merima ocaves @ 4 = kdcoso e 4 =0 to find.cos(6) + 4 = 0 de de- 4 d aa quen luoquency of obecaben = 100 MHz 8 2 3 de 3.10 100.109 a d = - 43 wete day the phase shaft 4² - I 2 dmin = 3 / 3 - 1.5m