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5.17 The frequency response of an ideal low-pass filter is -1/2 S2 > 0 |H(S2) = - -2 <92 < 2 otherwise ZH (12) = 0 1/2 12 < 0
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Oil = ارد) H| 2<rca { 0 Otherwise Zhvis) = { rzo -7% / rco j LH /w) Huw) = e ارد)H ist Can ap, written be T le -j ocrca Hin)

h(t) = 1 s Hijw) Hijw) etust du 1 | Rt -32 ]] + 1193. [ * *selatan + Selalan] hu) top [ [sent le hews [ }(4-2020) + +[-+*+]

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