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(1 point) Calculate S3, S4, and Sg and then find the sum for the telescoping series 1 1 S (+12) n=4 where Sk is the partial s

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Answer #1

S = 1 n+2 nt n-4 ) is the partial sum using ny S3 first 3 values of n ie. n=4, 5, 6 53 = t 5+1 (tor) ( 1 / 1 5tz) +*+-2) (5-51 SA sum of the terms when n=4,5,6,7 흰 SA 4+/ 442 + (-) (5th t4) + +9 H9 + (+1 + ㅗ ㅋ4245 그의 C 45 9-5 1) = 에 F 7 z + - - 4 I - + - +4 - 무 ( - 무) + (루- ) + (- - 구) + ( - 후) +S5 sum of terms when n=4,5,6,7,8 9 . Ss - ( ) + (-) + ( - ) + (-) + (-) T -+-+- + - - + TT 100 2. 2 - - 5 10 al 10 TO SE T +2• 7 - 구 5 표 + lim kd 하 K k) +) 1 - K42 1 lim 아 C 5. Kt2 K00 lim 그 lim a 노 2 kod 5 ko 아 - 이 [ K then, 90 m d 5 2 | Lio

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