int i = 33;
double d = 12.88;
int * iPtr = &i;
double * dPtr = &d; //
iPtr = &d; //
dPtr = &i; //
iPtr = i; //
int j = 99;
iPtr = &j; //
int i = 33; // An int variable with a value
double d = 12.88; // An double variable with a value
int * iPtr = &i; // Declared a pointer variable called iPtr pointing to an int (or int pointer) and Assign the address of the variable number to pointer iPtr
double * dPtr = &d; // Declared a pointer variable called dPtr pointing to an double (or double pointer)
// Assign the address of the variable number to pointer dPtr
iPtr = &d; //Assign the address of the variable number to pointer iPtr
dPtr = &i; //Assign the address of the variable number to pointer dPtr
iPtr = i; //Assign variable number to pointer iPtr
int j = 99;//declared j int variable
iPtr = &j; // assign the address of variable to pointer iPtr
Look at the following code and comment each line about how it works with pointer. int...
[C++ Language] Look at the following code and comment each line about how it works with pointer. int i = 33; double d = 12.88; int * iPtr = &i; double * dPtr = &d; // iPtr = &d; // dPtr = &i; // iPtr = i; // int j = 99; iPtr = &j; //
QUESTION 9 What will be the output of following code snippet? int a[3] = {1, 2, 3}; int *p = a; int **r = &p; printf("%p %p", *r, a); A. Different memory addresses printed B. 1 2 C. Same memory address printed twice D. 1 1 2 points QUESTION 10 What will be the output of following code snippet? int arr[4] = {1, 2, 3, 4}; int *p; p = arr + 3; *p = 5; printf("%d\n", arr[3]); A....
The following code snippet is for C++ int selection_Sort(int A[ ], int n) { int I, j, small, temp; for( i = 0; i < n-1; i++) { small = i; for(j = i + 1; j < n; j++) { if ( A[ j ] < A[ small ] small = j; } temp = A [ i ]; A[ i ] = A[small]; A[small] = temp; } } Please explain in rich detail the logic behind every execution...
Given the following Java code: class C { public int foo(C p) { return 1; } } class D extends C { public int foo(C p) { return 2; } public int foo(D p) { return 3; } } C p = new C(); C q = new D(); D r = new D(); int i = p.foo(r); int j = q.foo(q); int k = q.foo(r); (Remember that in Java every object is accessed through a pointer and that methods...
Translate the following code into MIPS code. Test (int i, int j) { int k; k = Double(i+1) + Double (j-10) return k; } Sub (int m) { int g; g = m + m; return g; } Assume the compiler associates the variable k to the register $s0. Assume the compiler associates the variable g to the register $t0.
C Language! Please, comment what each line of code does in the code below and answer this question: (sentence is fine) 1. Aside from pressing ctrl-(d/z) at the beginning of a line causing the getnchar() function to return NULL, is there any way to enter less than 9 characters? Code: void exer1(void) { char input[LEN]; char *check; getchar(); // Clearing character buffer. printf("Please enter 9 characters: "); // Prompting the user to enter // a specific input. ...
Question 2 (a) Provide a single line of C++ code that will declare a variable that points to a string value, the variable is named x. [2 marks] (b) You have array c declared as string *c [5]; Give the single line of C+ + code that will assign the string pointer stored in variable x (from above) to the third element of the array c. [2 marks] (c) Write a for loop that initialises the contents of each element...
Please, explain clearly each line of code with your answers. Question 1 Consider the following code snippet: int ctr = 0; int myarray[3]; for (int i = 0; i < 3; i++) { myarray[i] = ctr; ctr = ctr + i; } cout << myarray[2]; What is the output of the code snippet? Question 2 Consider the following code snippet: int cnt = 0; int numarray[2][3]; for (int i = 0; i < 3; i++) { for (int j =...
The following lines of code all have problems. Identify what
is wrong with each line of code
The following lines of code all have problems. Identify what is wrong with each line of code. a) for(j=0; j<= 10; j++) cout << prices[j]; b) int array = {1,2,3,4}; c) int arr[3]; for (arr = 0; arr < = 10; arr++) d) char k; for (k=0; k<= 10; k++)
Show how to get the big-Oh for the following code: void CountSort (int A[N], int range) { // assume 0 <= A[i] < range for any element A[i] int *pi = new int[range]; for ( int i = 0; i < N; i++ ) pi[A[i]]++; for ( int j = 0; j < range; j++ ) for ( int k = 1; k <= pi[j]; k++ ) cout << j << endl; }