| There are only two outcomes, i.e, either the insects will survive or they do not. | |||||||
| Hence, binomial distribution can be used. | |||||||
| The formula to be used is:- | |||||||
| P(X) = nCx * px * qn-x | |||||||
| Where, | |||||||
| P(X) = Probability of x outcomes | |||||||
| n= number of samples or trials | |||||||
| p = probability of success | |||||||
| q = probability of failure | |||||||
| Here, | |||||||
| n = 7 (there are 7 insects) | |||||||
| x = 4 (exactly 4 should survive) | |||||||
| p = q = 0.5 (since the probability of survival and not surviving is equal) | |||||||
| nCx = | n! | ||||||
| x! (n-x)! | |||||||
| 7c4 = | 7! | = 35 | |||||
| 4! (7-4)! | |||||||
| P(X = 4) = | 7C4 * p4 * q7-4 | ||||||
| = | 35 * 0.54 * 0.53 | ||||||
| = | 0.273438 | ||||||
| = | 27.34% | ||||||
| Therefore, the probability that exactly 4 insects will survive = 27.34% |
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