Question

Consider the following reaction:

      2NH4NO3(aq)+Ba(OH)2(aq)=2NH4OH(aq)+Ba(NO3)2(aq)

34.3 mL of 0.439 M NH₄NO₃ was added to 11.5 mL of 0.655 M Ba(OH)₂. Assuming that no reactant is in excess, what will the concentration of the formed NH₄OH be

Answer 1

soll. Given the volume of why nog (W) = 34.3 m = = 34.3 üter 1 1 0 = = 0.0343 üter concentration of Nity NO 3 (MI) = 0.439 M con centration (molarity) no. & miles rolume B-solution in liter .. no I moles of Nity NO - WhyNDg = M, Y 0.439 X 0.0343 mol 0.015 mol Here told that rea actand- Nity Noz and Balor) is excess that meam completty rearted. the balance reaction 2 N HY NO3(aq) + Ba(12), (09) 2 NHY OH (AR) + BA (103) aque volume of Ba(OH)₂ = 1-5 ml I 1000 malitor] = 15 ûter 0.015 üter :. Tofal rolume = 10.0343 + 0.0115) üter 0-0458 üteri from reaction mol "Hynuz produced 2 mol why sh 2 1 2 2 0.015 2 x 0. 015 다 mol 2 mity of 매 ot is 0.015 mol mly concentration of Niyot no. of moles of Nally OH total volume of solution in liter 0:015 M M [putting value 0.0458 0.3275 M М. - 0.33 M i ona is concentration of Niy 0.33M Scanned with CamScanner