Answer)
First we need to find the difference in between after and before
0.7, 0.4, 0.5, 0.2, 0.8
Now we need to find the mean and s.d of the differences
Mean = 0.52
S.d = 0.2387
N = 5
Test statistics t = (mean difference)/(s.d/√n) = 4.871
Degrees of freedom is = n-1 = 4
For 4 dof and 4.871 test statistics
P-value from t distribution is = 0.004
As the obtained p-value is extremely small
We reject the null hypothesis Ho
B)
Effect size = mean difference/s.d = 0.52/0.2387 = 2.18
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*show work by hand*
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