Question

Nancy plans to invest some money so that she has $3,600 at the end of three years. Determine how much should she invest today
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Answer #1

Correct Answer:

Amount Required to be invested

A

$ 3,173.80

B

$ 3,108.80

C

$ 3,083.10

D

$ 3,074.50

Working:

A=

P*(1+R)^T

Therefore:

P =

A/(1+R)^T

A: Compounded Daily

R

4.2% / 365 Days =

0.0115%

T

3 * 365 Days =

1095 days

A

3600

P =

A/(1+R)^T

A

$        3,600

1+R

1.0001151

T

1095

(1+R)^T

1.1342739

P = A/(1+R)^T

3173.8

B: Compounded Monthly

R

4.9% / 12 Months =

0.4083%

T

3 * 12 Months =

36

A

3600

P =

A/(1+R)^T

A

$        3,600

1+R

1.0040833

T

36

(1+R)^T

1.1580073

P = A/(1+R)^T

$    3,108.8

C: Compounded Quarterly

R

5.2% / 4 Quarters

1.30%

T

3 * 4 quarters

12

A

3600

P =

A/(1+R)^T

A

$        3,600

1+R

1.013

T

12

(1+R)^T

1.1676518

P = A/(1+R)^T

$    3,083.1

D: Compounded Annually

R

5.4%

5.4%

T

3

3

A

3600

P =

A/(1+R)^T

A

$        3,600

1+R

1.054

T

3

(1+R)^T

1.1709055

P = A/(1+R)^T

$    3,074.5

End of Answer.

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