Question

MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The relationship between the amount of money that Canon Precision Instruments spends on advertising and the company's total sales is given by the following function where is measured in thousands of dollars S) - -0.002.00? + x + 500 x 200) Pind ), the rate of charge of the sales with respect to the amount of money spent on advertising S)- At whatrate in dollars per thousand dollars of advertising) are Canon's total sales increasing when the amount of money spent on advertising is $100,000 $ per thousand dollars of advertising At whatrate (in dolars per thousand dollars of advertising are Canon's total sales increasing when the amount of money spent on advertising $150,000 5 per thousand dollars of advertising Are Carnon's total sales increasing at a faster rate when the amount of money spent on advertising is $100,000 $150,000 $100,000 $150.000

Answer 1

S(x) = -0.002 x3 +0.6x2 +42 +500 (Ocn 4200) s'(x) = rate of change in sales with respect to the amoun of money spent ou advertising s'(x) = a (su) dx d (sx) = a (-0.002 x3 +0.6x² + 4x +500 ) da - d (-0.002x3) + d (0.6%?) + d (44)+ d (500) du du du dr W -0.002 & (x3) + 0.6d (x2) + d (40) + 0 ( r 10 -0.002 x3 x 2 + 0.6x20 + 4 s'(x) -0.00642 + 12x +4 at Forn=100 s'(100) = $64 -0.0066100) + 12 (100) +4 thousand dollars of adu. thous- b) For n = 150 S'(150) = -0.006 (150)2 + 1.2(150) +4 = $49 pu and dollars of adu. at a faster advertising So, cannon's total sales are increasing at a rate when the amount of money spent on is $1,00,000