Question

Find the measure(s) of angle a in sin(20) +3=4, where ose<2. Give exact answers and show all of your work.

Answer 1

Solution (2) v2 Sin (20) +3=4 ; oso san > = 4-3 = 1 52 sin(20) Sin (20) - I (2 sin (4) na teor > 20 = ♡ รา 2 tenho รา: 0 9 - o 8 n=1 o = 1 / 1 iT - 31 n=2 o= T +7 gir m=3 O- 3iT 2. 317 22 T m-4 YIT of > 2 Elo o should be less than 21 thus 3 IT GIT 117T 8 37

(20) cosere ) - 30 -21-30 - IT - 2 -31 - 2 1 FIT n -- vertical asymptotes >x=1T, 21, 0, -, -21 seca 1 -21 21 T 22 3/2 2 TT vertical asymptote ->x=" , 34, -2,-3"

sange is, y E 6oo,-1]U (1,00) graph neither fouches x-asis not cuts it therefore, no - x-intercept Now As per the statement it is true that both have vertical asymptotes, both have same range, and both have no-x-interceptos But their domain is different which makes them different functions, other different names. For example y = coseca Real domain is R - {m} ; DEI than having w Real XE y = sec x domain is XER-{{n+1)13. ;