Question

A rare form of malignant tumor occurs in 11 children in a​ million, so its probability...

A rare form of malignant tumor occurs in 11 children in a​ million, so its probability is 0.000011. Four cases of this tumor occurred in a certain​ town, which had

18 comma 57518,575

children.

a. Assuming that this tumor occurs as​ usual, find the mean number of cases in groups of

18 comma 57518,575

children.b. Using the unrounded mean from part

​(a​),

find the probability that the number of tumor cases in a group of

18 comma 57518,575

children is 0 or 1.

c. What is the probability of more than one​ case?

d. Does the cluster of four cases appear to be attributable to random​ chance? Why or why​ not?

a. The mean number of cases is

nothing.

0 0
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Answer #1

Answy: Given that probability for children is 20.000011 a) mean of number of cases in groups (XN) = 0.000ll * 57518,575 20432o De P{x>1} a % do not d). NO, indeed cluster of Four cases + appear to be attributable to random chance. Because by random c

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