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A 10 350 20 KM 200 TIUT SOLVE FOR THE FORCE IN MEMBER AB O A AB - 30.16 KN B. AB - 17.60 KN CAB 31.60 KN D. AB = 17,43 KN

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By using Hethod of joint 00 Vio 35 20 10 c Fac 35 10 20 FAB sso 20** Now applying E Fx=0 E fy=0 FAC8055 20 Sind FAB SMD E Fx=

Charpawne NY 09.1E FAB a suo smoue huo ubisan Ny og 16- FAB ody = 3 s ewis- rsa is oe (sstof uis Oy (ss-08) uis) aty suis-ut

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