Homework Answers
Given data :
Take off speed of jet (V) = 165 mph
= (165*0.44704) m/s
= 73.762 m/s
time (t) = 2 s
assumption:
- fighter jet starts from rest. i.e (U = 0)
- acceleration will remain constant during take off
from equation of motion
V = U + a*t
where a is acceleration of jet
73.762 = 0 + a*2
a = 36.881 m/s2
so the deck space needed to allow a fighter jet take off from an carrier
S = U*t + a*t2/2
S = 0*2 + 36.881*4/2
= 73.762 m
thus deck space needed is 73.762 m
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