Question

Job Seeker (k) 1 2 3 4 5 5 6 7 8 9 10 11 12 13 14 15 Interviews (Xi) 3 5 114 6 7 6 3 Job Offers (Y) 0 2 1 2 2 4. 3 5 1 4 6 100 7 4 8 1 1 8 4 2

Answer 1

solution of o x= number of interviewers and number of Joboffers represented by y let the least square regression line as yi=Bootsi ai. d=1,2,-- where Bi- & (ni-n) (yi-n) & Cai_82 d Bo= 9 - Bîr with help of the data n-15,76= 5:1333 9 = 32 { cai-222 = 123.7333 i=1 =) & (ai-2) cyi-g) = 45:6 il Br = 45.6 - 0.3685 123.7333 Bo^= 3.2-(0-36 85x5-1333) = l. 3082 R = 0.3685 Bo=1.3082 |-3092) @ If the null hypothesis is that B,=0.8 Alternative that B+0.8

sh Sx²= 2 Cai_^) 0.2489 El Cyi- Bol Brai)? =5.1996 n-2 = 5-1996 standard error of fî as sel ✓nsor -0.2050 Selt) 2050 otto: B=0.8 vs H,: B160.8 level of significance deoos Test statisticg= t= BABI BI-BI N+(1-2) sel Bî) t= 0.3685-0.8 02050 -0.4315 z-2-1049 0:2050 F=-2.1049 14 È value o Paralue= 2 PC tig<t) p-value = 2.P (tiz (-2.1049) P-value=0.0553

? m & p-value is greater than a fail to areject Ho m Construct 95% confidence interval for Bi B^_0:3685 se(B^)=812050 95% CI for Bi as g= / XỬ Lo50) [BA PÀ- 170.025, 13) se(RM), pittoo2S13) Self^) [0.3685-(2.1604*0.2050 0:3635+(2-46044 =) ( 0-3685–0:4423,0-368570.4423 =) (-0.0744, 0.8114) 95% confidence then the toue value of Bi lies in the above confidence interval yes, agree in favour of cathy's statements