Question

1- a- How do you prepare 600 mL 4 N H₂SO₄ solution using 50% Sulfuric acid stock solution (d: 1.403 g/mL MW:98g/mole)?

b- If you took 10 mL from this sulfuric acid solution (4N) and diluted to 1000 mL, what would be the % (w/v) and ppm concentration of the final solution.   

Answer 1

6oo - 167.7 = 433.3 ml of water to So, to make boome of UNH₂S0u. need to add 167.7 ml of of stock sath and then add ع کیا ite Ane Males of H₂SO4 in lome of 4 Nason is given as a Molarity = Normality n-factor Soy moles_of_H2SO4 = 2* Lox1036 = 2x10-2 moles H₂ Soy it is diluted to looo mle - 2M 2 Now it is So, the final son contains 2x10-2 moles H₂SO4 Lewater in 1000 ml of म So, mass of H₂SO4 = 2x 10-2 moles x 98 g/mol. = 1.96 grams Nolume ol 0 loo = المد So % (w/v) = 1.96 x 100 =10.196% ܘܘܘܠ

is given Concentration in ppm Clin ppm): Mass of Hesoy in ing) Volume sol Enl) 19 6x 103 mg IL 1960 ng LL of = 19 60ppm (1 ppm Ing /