Question

You want to measure the molecular weight of a protein molecule so you measure the osmotic pressure of a protein solution you make. If 0,10 g of protein is dissolved in 5.0 ml. of solution, n = 0.05 atm at 25°C. What is the molecular weight of the protein? 820 g/mol Anamn

Answer 1

Given: mass of Botein 0.log Volume de solution 5.0mL osmotic Pressure = 0.05 atm Temperature - T= 25°C (25+273:15) k T = 298.15 K Osmotic Bessure is given by CXRXT (-) molarity) UT 1 کیا 1000 x RXT X V (mL) n Osmotic pressure we mass of protein My molecular weight of protein R=0.0821 L atmik' molt Rt universal gas constant T→ Temperature in Kelvin V1 volume of solution IT = W x 1000 x R XT M vmL) By substituting the values o os atyr atyn 0.109x1000 X0-0821 Katm i molk 298-15 M 5.04 M o lo x1000 X0.0821 x 298.15 g Dios x 5 mol 9791-2 g/mol Molar mass of protein 9791.2 g/mol Answer Extra Information Molarity C = number of moles volume of solution (inL) Number of moles = - Given mass Molar mass 3 JE IL- 1000 ml molarity = c = 6 1000 VML) M