Question

The energy needed to convert 2 kg of ice at -10 °C to water at 10 °C will be { Constants Given: Specific Heat of Water = 4186 J/kg ºc, Specific Heat of Ice = 2100 J/kg ºc, and Latent Heat of Fusion = 3.33 x 105 J/kg. }

Answer 1

In this process there are three steps in which the heat is exchanged. the temperature of ice will rise from minus 10 degree Celsius to zero degree celsius then the ice will convert into the water and then the temperature of water will rise from zero degree celsius to 10 degree Celsius.

8 Formula used : Osmsso M = mass, so specific neco, Heat required to take & -mL temp.diffe 1. latent float - 10°c toic ice from msice $(2xg) (21000 lley or oc) ( 10k) 0 42000 I. - 0.42 x rost teat required to Connert ice at doc to water Q ML 2 (2 kg) ( 3.33x105) 6.66 xios y (2) raise water at 0°C to +10°c. teat required to Oz (2kg) e mswater so Qly) (4186) Crok) Qg 0.837 xong 3 Total heat Qi to Iz 6.66 Xlor +0.837x10 0.42 Xiort Ta 7.917 8 Ion