Question

Zn + HCl ---> ZnCl2 + H2(g)

The total volume of collected gas over water at 65oC was 1728 ml at a total pressure of 845 torr. If you used 325 ml of HCl for the reaction, what molarity of HCl would be required to produce the correct amount of Hydrogen?

Answer 1

Zn + HCl Enely + H₂(8) Volumel Pressure (b) of the Colleded gas ine 845 tonn respectively, H2 ane and 1728 md temperature, T=6502= 65+273) K = 338k volume, v 1728 mL = 1.728 L 11 845 tonn b 845 760 alm Pressure, [760 700 tonn = I alm 1.1118 am of collected then f n, moles acconding ideal low fas b da ART Þ AT 0.0693 mole (1. 1118 alm) x 1.7282 (0.082 Lammo 1"K") x(3 38k) moles of Produced. have beon Has e 0.0693 balance then the equation. let us Now, balanced equation 2nd2 + + Ha an 2 HCI I mole H₂ the balanced equation, from HCl. Produced Con 2 mole Produced of have been 0.0693 moles from (2x0.0693) IHCl. mole 0.1386

325 of mL solution should Contain 0.1386 mole HCl, Hence, moles of HCl IL - 1000 mL solution = 0.1386 X1000 mole 0.426 mole 325 Hence required molanity of 0.426 mole/L.