Question 6 14.3 pts Let h be a function such that h'(x) = 2x3 + 3x2...

Question

Question

math calculus

Answer 1

Answer #1

Given 6(x) = 2x² + 3x²-12%. (2x+372-122 d = 2(32²) + 3(2x) -12. b(x) = 6x² +62-12 Inflection points are those where-6(x)=0

Answer 2

Similar Homework Help Questions

Question 7 14 Let f be a twice differentiable function, and let f(6) = 7, f'(6)=0,...

Question 7 14 Let f be a twice differentiable function, and let f(6) = 7, f'(6)=0, and f" (6) = 0. Which statement must be true about the graph of f? (6,7) is a local minimum point (6,7) is a local maximum point (6,7) is a global maximum point There's not enough information to tell. (6,7) is a point of inflection (6,7) is a global minimum point Question 5 14.3 pts Let f be a twice differentiable function. y С...
Let h be a function such that h' (2) = 2.03 + 3.02 – 12.c. For...

Let h be a function such that h' (2) = 2.03 + 3.02 – 12.c. For what values of does the graph of h have a point of inflection? 2 2 00 1 ) 1
Question 17 5 pts Suppose f(x) = [Vť – 5t + 6.25 dt. For which positive...

Question 17 5 pts Suppose f(x) = [Vť – 5t + 6.25 dt. For which positive value of x, does f'(x) equal O? 0 O 2.5 There is no such value of x. V2.5 O 1 Question 16 5 pts Use the Fundamental Theorem of Calculus to find the derivative, f'(x), of va t2 f(x) = S. dt. 4+ 3t4 1 x2 4 + 3x4 х 4 + 3x2 a 4 + 3x2 2 (4 + 3x2) -C 2+(4+ 3x2)...

Question 19 3 pts 5 1 0 Details Find all the values of x where the...

Question 19 3 pts 5 1 0 Details Find all the values of x where the graph of f(a) 2x3 – 30x2 + 542 – 6 has a horizontal tangent line. The smaller one is x = and the larger one is x = Question 20 3 pts 5 1 0 Details Consider the function f(x) = 3x2 – 8x + 1, 0 < x < 8. The absolute maximum of f(x) (on the given interval) is at X =...
The DERIVATIVE F"(x) of a function f(x) is given by X f'(x)= 1 + x +...

The DERIVATIVE F"(x) of a function f(x) is given by X f'(x)= 1 + x + 2x3 What is the x-coordinate of the inflection point of the graph of f(x)? O A. X = 0.393 OB. X= -1.607 O c. X=0 OD. The graph off has no inflection point. O E. X = 0.807
Question 11 10 pts The derivative f'(2) of an unknown function f(x) has been determined as...

Question 11 10 pts The derivative f'(2) of an unknown function f(x) has been determined as f'(x) = (x - 2)(+3)2. Use this derivative to find the intervals where the original function f is increasing/decreasing. Then find the x-values that correspond to any relative maximums or relative minimums of the original unknown function f(x). O no relative maximum; relative minimum at x=2 relative maximum at x=-3; no relative minimum O relative maximum at x=2; relative minimum at x=-3 relative maximum...

QUESTION 10.1 POINT Let h(x) = f(g(2). If f(x) = –3x2 - 4x +2 and g(x)...

QUESTION 10.1 POINT Let h(x) = f(g(2). If f(x) = –3x2 - 4x +2 and g(x) = -1° + 3x + 2, what is h'(-1)? Do not include "W'(-1) ="in your answer. For example, if you found 1(-1)=20. you would enter 20. Provide your answer below:
allowed time frame. Question 11 4 pts Find the derivative of the function. x3 f(x) =...

allowed time frame. Question 11 4 pts Find the derivative of the function. x3 f(x) = In X X3 O 3x2 x3-2 O 3x2-1 x(x3 - 2) O 2x3 + 2 x(x3 - 2)
Question 13 (1 point) How many critical numbers does the function f(x) = 2x - 3x2...

Question 13 (1 point) How many critical numbers does the function f(x) = 2x - 3x2 + 4 have? 3 2 0 Question 14 (1 point) The vertical asymptotes of X are f(x) = O x=2 and x = 1 Oy= 0 and x = 2 x = 2 and x = -2 x= 0 and x = 2

Consider the following. f(x) = 1 4 x4 + 1 2 x3 − 3x2 + 4...

Consider the following. f(x) = 1 4 x4 + 1 2 x3 − 3x2 + 4 Find f '(x). f '(x) = x3+ 3x2 2−6x Find f ''(x). f ''(x) = 3x2+3x−6 Find the x-values of the possible points of inflection. (Enter your answers as a comma-separated list.) x = Determine the intervals on which the function is concave up. (Enter your answer using interval notation.) Determine the intervals on which the function is concave down. (Enter your answer using...