Question

8. A mass m is connected at the lowest part of a vertical spring with constant k. Tied to this mass, there is another mass m hanging by a rope (see Figure 1). Both masses are subjected to a simple harmonic vertical movement of amplitude A. At an instant when the acceleration of the masses is maximum and upwards, the The rope that unites the masses breaks and allows the mass below to fall to the ground. Find the resulting range of motion of the mass that follows with the spring.

MW k m2 A Cuerda m2 А Figura 1: Dos masas se mueven en sincronía antes de que rompa la cuerda.

Answer 1

solution to feel mass 22m furen Amplitude - ser D con om W, K 2m 2 Energo ad extreme point formule U= ₂mw,A,2 Ź (2m) N = 2x2mxK 24 2 K 2 the A2 A2 KAZ J 2 Novo energy stored in rope is broken then spring remain conser ved А do, freuen mass om IA Al Wir Amplitude aA' VA energy will be U₂ = t moral (m) (V) 22 XAIR L KA2 U = U2 So, KA? 19.2 đ لا ALFA to, amplitude will be same for resulting motion.