Question

11) In the circuit, what is the charge on Co if Cs a) None of these b) Q-10c 王丁 G1 C2

Answer 1

Given C_1 = 1 F C_2 = 1 F & C_3 = 2 F Delta V = 5 V From figure 1 we can see that C_1 and C_2 are in parallel whose combination is in series with C_3 Therefore C_1 Vertical-bar Vertical-bar C_2 = C_1 + C_2 = 2 F Now the two capacitors are in series, Therefore Total capacitance of circuit is, 1/C_eq = 1/C_1 Vertical-bar Vertical-bar C_2 + 1/C_3 1/C_eq = 1/2 + 1/2 Therefore C_eq = 1 F \r\n So total charge stored by circuit is given by q = C Delta V rightarrow Q_total = 1 times 5 = 5 C Now we move back in the circuit. Fig.3 is made up by two capacitors in series (fig 2), and in series combination, each capacitor have same charge as of its equivalent capacitor (parallel combination has same potential difference). So charge on C_3 and (C_1 Vertical-bar Vertical-bar C_2) is 5 coulomb. Therefore Charge on C_3 = 5 C