Question

10.43 Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the vol- ume of a particular sample of Cl2 gas is 8.70 L at 119.3 kPa and 24 °C. (a) How many grams of Cl2 are in the sample? (b) What volume will the Cl2 occupy at STP? (c) At what temper- ature will the volume be 15.00 L if the pressure is 116.8 kPa (d) At what pressure will the volume equal 5.00 L if the tem- perature is 58 °C?

Answer 1

Ch.gas volume of h q9s = 8.70L <עלמ: ! pressume = 119.3kPq = 11 J.3 X 10 Pa= 1|9300 Pa we know; 1013 25 Pa = latm Hence; presue = 119300 101325 = 297 K Temp= 24°C Applying Ideal · qai Equalion; PV- NRT n= 1-18X 8-70o O •0821 X 27 n= 0.42 mole (a) mass of C, m same 2 moles X molar mass c0.42 X 35-5 14.95 gram b, volume at STP ( mole = 22-4L 0.42 mole = g.408L 1olume af will the U2 %3D at STP ercaupy =9.408L Ic) At volume = 15.00L nd pressure = 116.8 KPq; = Ta k. %3D Temperature Applying; T2 T1

119.3 X8.70 116.8 X 15 → T = 116:8X15X297 119.3 X 8-70 501.34 K

At 228.34°C. i ît will beve volume = 15-00L and þressure = 116.8 kPa ) Temperature = 58°C %3D = (273+58) = 331K * volume 5.00L let pressure P2 PiV, -R V2 Te. Ti P2= PIVIT2 P2= 231. 35 Kpa P2 = 231.3 kPa At pressure = 231.3kPa; H will have volume =5-00L and Temp=58°s
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