Question

Find the confidence interval likely to contain the popalation parameter A nample stadistic and margin of errer are given. of interest and answer the question 23) 23) Ten yeam ago, amending to government records r7% of the population of Elmwood had no health inaann". This wara poll revealed that 206% were without insurance. The margia of eror was 2.8 percentage p percentage without insurance this year. Can we conclude that the percentage without insurance has increased from sen years ago? oints. Find a confidence interval for the truse Use the 68-95-997 rule to solve the problem. 24) The time it take Cloudia to drive to work is normally distributed with a mean of 48 minutes and a standand deviation of 5 minutes, less than 53 minutes to drive to work? 24) What percentage of the time will it take her Solve. 25) A line is subdivided according to the golden ratio, with the smaller piece having a length of 7 meters. What is the length of the entire line? 25) Form a tiling from the given figure using translations and reflections. 26) 26)

Answer 1

23)

We know that $(100-\alpha)$% CI for true proportion is given by:

$(p\pm Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}})$

Since the percentage for the current year is 20.6% and the margin of error is 2.8%, so the confidence interval for true percentage is given by:

$(0.206\pm 0.028)$

$(0.178,0.234)$

So, the confidence interval ranges from 17.8% to 23.4%.

Since 10 years ago the proportion was 17%, so based on the confidence interval, we can say that the percentage without insurance has increased from 10 years ago.