Question

21 Analog Part-(20p) Attention! Write down all the solutions and take a photo of those pages and sent them to“ student solutions notes”. Choose at least ONE question in this group (GROUP A) (20p) AI 4 220V 50Hz Vintrms}=10V Vout 500ohm a) By giving the necessary explanations, draw Vin(t) and Vout(t) versust on the separate graphs (on the same page!) in the same time scale (assume Vo=l Volt and V2 = 1.4). (16p) b) By giving the necessary explanations, find the output voltage (Vout) and load current (IL). (4p)

Answer 1

21) from circuit ! Vinalov soms) Vpeak = 10 x S a 10 *(1.4) = 14V Mathematically Vin = lo xk sin (wel lvin= 14 sin (wt) I volts. * Considering diode as ideal its cut-in volooge V3 = ov. ;) when Vindo Diode voltage VAK so o Diode conducts. Vout Then Vout = Vin - I Load = 14 sin (wt) v soon ) when Vinco i Diose velfage Vakco y Diode does not conduct. Then Vout ov Leb T=ET RA wa 1 14 o all E -140 Nout 14V TT 21 3 TT >t 6) Vout s Yout(ti.de T LT Şiu sin(t)ost + oodt +*o.st] 2T <T) vout = [4 C-cost) !" +o] - [ Casfo) –cos(w] = ['--1] Yout . 14 T 4.4563 volt 14 * I load Yout Sooj Iload 58.9126 xió 3A8.9126 mA Soo TT