Question

hce bound on the standard deviation. 8-46 The sugar content of the syrup in canned peaches is nor- mally distributed. A random sample of n 20 cans yields a meat o-side nt

Answer 1

Answer:

a)

The box-plot of the speed-up data given below does not provide good support for the assumption that the population is normally distributed. But the normal probability plot supports it better. This can be caused by a small sample size. Boxplot of Speed-up 5.00 4.75 4.50 4.25 4.00- 3.75 3.50 dn-paads

Probability Plot of Speed-up Normal 99 Mean 4,313 StDev 0.4328 N 13 95 AD 0.233 P-Value 0.745 80 70 60 50 40 30 20 3.5 4.0 4.5 5.0 5.5 Speed-up un 90 10 Percent

The sample mean is: 3.775302.. +4.600101 4.313222 13 The sample standard deviation is: z(Hx) 1 (3.775302 4.313222)2 S = _ (4.600101 4.313222)2 13 1 0.432802 _ df n 1 13 1 12 b)At 95% confidence, for two-sided confidence interval, critical value of tis t 2.179. The two-sided 95% confidence interval is: 0.432802 tt n 4.313222 2.179 = 4.313222 t 0.261539 = V13 Or (4.051683, 4.574762) c)At 95% confidence, for one-sided lower confidence bound, critical value of tis t 1.782. The 95% one-sided lower confidence bound is: 0.432802 S 4.313222 1.782 Vn 4.313222 0.213942 4.099281 -t _ _ V13