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5. 116.66 pointsNoErgStatis1 7.PO50. Determine the surface areas in mm2 and the volumes in mm3 of the bodies of revolution ob

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(390 195TT 15 A 2TT (38025 t-57037 . 5 + 57037-5 = 138 11 5607 A = 1-8257x106mm 3 TT 6.4415 3(4715+195(55) (195) 之 +-(9-1-5)(195) + (9で5+雙)(TT x195) 々TT ( 38025 + 5To37-5ナ19012-5 5912.53 A = j.oq70LfX106 mm

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