Question

The Henderson-Hasselbalch equation connects pH to pk, by relating pH to the relative amounts of the acid and conjugate base. The equation is: [A], pH = pKa + log [HA]' A. If you had an acetic acid solution at pH 4.75, what would the ratio of acetic acid to acetate 4. be? (Сн,соо у сн, соон) - ([CH3CO0¯], [CH3COOH], B. What if the solution pH was 4.27? C. What about pH 5.05?

Answer 1

Answer: The Headerson - Hasselbalch equation, pH = pka +log CAI THA h+ сна Соон — сиз Соо- Acetic Acid Acetate con We known, Pka value of CH3c00H = 408 6 A gf pH= 9.75 , Peet the value in formala 4. — — 4-6 + lon (chgtoo) Ссиз Соонд 4:25 - 4-8 – 14 Сенз соо- Г сиз соону е спасер - - - 0.05 [СН2Саон] Taking Antilog [cnycoo-) - Гch Cooh) Autilog (-0.05 ] Гch (op - Гcg Cophy - 0.891 gf pH = 4.27 they ration is 4:22 - 4-6 + lea Сch3c00 ] Гch, Cooh) 4. 22 - 4 - 8 = lea C cng Coo-) Сс зори7

log (CH3cool 2 - б. 53 Ссиз соон] Taking Antilog (ons too ) - Push lon (-0.53) Гcni Coorj Гch Cool - 0.2 95 Ссну соонд If pH = 5.05 then the ration is 5.0s = 4-6 +1e2 Ссну Coo-) [CH3COOH) os - 4.0 = lea Гсид Coo-] Сch3 Coph] . [ck too - 0.25 LCH3Cooh] Taking Antilog [chycoo] = Antilug (0.25) Гccoon) Гcm (oo си Соону) - 1.22-2 "Please rate it "