Question

Problem #2 (25 points) - The True Hanging String Shape After solving for ye(2) for the scenario in Problem #1, show that the mag- nitude of the tension in the string is given by the expression T(X) = To cosh (Como) where To = Tmin is the minimum tension magnitude in the string which occurs at the bottom point of the string, and then show that the maximum tension magnitude occurs at the top points at x = ta, and determine this maximum tension magnitude (Tmax) in terms of Tmin, po, and a. Problem #3 (25 points) - Minimum and Maximum Tensions Using the same scenario as in Problems #1 and #2, show that 8h Tmin= Pog(L? – 4h) and I - Pog(L+ 4h2) 8h give the minimum and maximum tension magnitudes, respectively, in the string. Hint: You may use the fact that L= / 11+(1. (x))dx and cosh? (2) - sinh?(z) = 1. Then compute Tmin and Tmax using the inputs: L = 50 m, m = 5 kg, h=1 m, and g = 9.8 m/s, which are inputs for a heavy string (or a uniform wire such as a telephone wire).

I need help with problem #3, please and thank you!

Answer 1

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