Question

Please do both parts (in Java); thanks!

An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3^3 + 7^3 + 1^3 = 371. Draw the flowchart and write a Java code to find ALL Armstrong number in the range of 0 and 999. You should write your code in two ways: (Yes as if you are solving the problem twice) A- I would like for you to write the whole code as a method that will output all Armstrong numbers, which means in main you have a method call only. public static void Armstrong() {//put your code here//You are generating the numbers and checking if every number is an Armstrong one} In main you are only calling the method B- This time you are going to write a method that returns back a true is the number is an Armstrong one, false otherwise public static Boolean IsArmstrong (int num) {//in this code you are just checking if the number passed to this function (num) is an//Armstrong one and you are returning true if so, otherwise you should return false} In main you are generating the numbers within the loop and you are calling IsArmstrong for every number. If the returned value is true, you will output the number.

Answer 1

part A:

import java.util.*;

import java.lang.*;

import java.io.*;

class Abc
{
public static void Armstrong()
{
int n,rem,arm; //rem for remender,arm for armstrong
for(int i=0;i<=999;i++) //loop for finding armstrong number b/w 0-999
{
arm=0;
n=i;
while(n>0)
{
rem=n%10;
n=n/10;
arm=arm+(rem*rem*rem);
}
if(i==arm)
System.out.println(i); //printning value if Armstrong
}

}
   public static void main (String[] args) throws java.lang.Exception
   {
       Abc c = new Abc(); //declairing object of class Abc
       c.Armstrong(); //calling method
   }
}

part B:

import java.util.*;
import java.lang.*;
import java.io.*;

class Abc
{
public static Boolean IsArmstrong(int i)
{
int n,rem,arm; //rem for remender,arm for armstrong
arm=0;
n=i;
while(n>0)
{
rem=n%10;
n=n/10;
arm=arm+(rem*rem*rem);
}
  
if(i==arm)
return true; //if number is armstrong return true
else
return false;

}
   public static void main (String[] args) throws java.lang.Exception
   {
       Abc c = new Abc(); //declairing object of class Abc
       for(int i=0;i<=999;i++) //loop for finding armstrong number b/w 0-999
{
   Boolean isTrue=   c.IsArmstrong(i); //calling method IsArmstrong
   if(isTrue==true) //if return true print value
   System.out.println(i);
}
   }
}