Question

PART 1: DATA TABLE 1 Identity of each metal M1 = CadmM2 = 2inc M3 = Lead whola... - tium Ms Wiike Voltaic Coll (metals used) M: /M2 Zinc M /M M /M M /M M /M Measured Potential Metalat (+) lead Metal at (-) load (V) (Red clip) (Black clip) 0.358 Cadium 0.262 Lead Cadium L 0.768 Whodatium Cadium 0.155 Nickel I Cadium 0,620 Lead Zinc I 1.127 whodatium Zinc 0.513 I Nickel Zinc 0.507 I Whodatium Lead 10.107 Lead Nickel 0.014 whodatium Nickel M /M M /M M/MA M /M Questions 1. Arrange the five metals (including M1) in Data Table 1 from the lowest reduction potential at the top (always at the (-) lead) to the highest reduction potential at the bottom (always at the (*) lead). Metal with Highest Reduction Potential, e Metal with Lowest) Reduction Potential, e (V)

Answer 1

Metal with Highest (+)Reduction Potential

M4

M3

M5

M1

M2

Metal with Lowest (-)Reduction Potential

More Reduction Potential means more Reduction takes place.

As we know, + is taken as cathode and - is taken as anode, and the formula is -

Ecell=Ecathode-Eanode or Ecell=Ereduction-Eoxidation because reduction occurs on cathode and oxidation occurs on anode.

BY data provided in table-

M1/M2 -  Ecell=EM1-EM2 i.e. Ecell=Ereduction-Eoxidation i.e. M1 undergoes reduction over M2. Hence the order of reduction potential is- M1 > M2

M1/M3 -  Ecell=EM3-EM1    i.e. Ecell=Ereduction-Eoxidation i.e. M3 undergoes reduction over M1. Hence the order of reduction potential is- M3 > M1

M1/M4 -  Ecell=EM4-EM1    i.e. Ecell=Ereduction-Eoxidation i.e. M4 undergoes reduction over M1. Hence the order of reduction potential is- M4 > M1

M1/M5 -  Ecell=EM5-EM1    i.e. Ecell=Ereduction-Eoxidation i.e. M5 undergoes reduction over M1. Hence the order of reduction potential is- M5 > M1

So the overall order is- M3,M4 ,M5 > M1 > M2

M2/M3 -  Ecell=EM3-EM2    i.e. Ecell=Ereduction-Eoxidation i.e. M3 undergoes reduction over M2. Hence the order of reduction potential is- M3 > M2

M2/M4 -  Ecell=EM4-EM2    i.e. Ecell=Ereduction-Eoxidation i.e. M4 undergoes reduction over M2. Hence the order of reduction potential is- M4 > M2

M2/M5 -  Ecell=EM5-EM2    i.e. Ecell=Ereduction-Eoxidation i.e. M5 undergoes reduction over M2. Hence the order of reduction potential is- M5 > M2

So the overall order is- M3,M4 ,M5 >    M2

M3/M4 -  Ecell=EM4-EM3   i.e. Ecell=Ereduction-Eoxidation i.e. M4 undergoes reduction over M3. Hence the order of reduction potential is- M4 > M3

M3/M5 -  Ecell=EM3-EM5    i.e. Ecell=Ereduction-Eoxidation i.e. M3 undergoes reduction over M5. Hence the order of reduction potential is- M3 > M5

So the overall order is- M4 > M3  >   M5   

M4/M5 -  Ecell=EM4-EM5    i.e. Ecell=Ereduction-Eoxidation i.e. M4 undergoes reduction over M5. Hence the order of reduction potential is- M4 > M5

Hence the complete and full order of the reduction potentials of metals from highest to lowest order is-

M4 > M3  >   M5 > M1 > M2