ICE Table:
[CO] [H2] [CH3OH]
initial 1.0 2.0 0
change -1x -2x +1x
equilibrium 1.0-1x 2.0-2x +1x
Given at equilibrium,
[CH3OH] = 0.5
+1x = 0.5
x = 0.5
Equilibrium constant expression is
Kc = [CH3OH]/[CO][H2]^2
Kc = (+1x)/(1.0-1x)(2.0-2x)^2
Kc = (+1*0.5)/(1.0-1*0.5)(2.0-2*0.5)^2
Kc = 1.0
Answer: e
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rating first right answer. Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) A reaction mixture in a 5.19-L flask at a certain temperature initially contains 26.5 g CO and 2.36 g H2. At equilibrium, the flask contains 8.64 g CH3OH. Calculate the equilibrium constant (Kc) for the reaction at this temperature.
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7) Given the following reaction: CO(g) + 2H2(g) = CH,OH(g) In an experiment, 0.57 mol of CO and 0.65 mol of H, were placed in a 1.00-L reaction vessel. At equilibrium there were 0.35 mol of CO remaining. Ke at the temperature of the experiment is a) 17.5 b) 12.7 14.3 d) 0.132 e) None of the above