Question

Part A An electron moves in the magnetic field B 0.440i T with a speed of 1.50 x107 m/s in the directions shown in the figure. For each, what is magnetic force F on the electron? (Figure 1) Express vector F in the form of F, Fy, F, where the x, y, and z components are separated by commas Submit Request Answer gure 1 of 1 Part B Express vector F in the form of F, Fy, F, where the x, y, and z components are separated by commas 45 Submit Request Answer

Answer 1

v^vector = -1.5 times 10^7 j^^B^vector = 0.44 i^^T F^vector = qv^vector times B^vector = -1.6 times 10^-19 times [(-1.5 times 10^7 j^^) times 0.44 i^^] = -1.056 times 10^-13 k^^N 0, 0, -1.056 times 10^-12 N v^vector = -1.5 times 10^7/squareroot 2 j^^+ 1.5 times 10^7/squareroot 2 k^^F^vector = -1.6 times 10^-19 times [(-1.5 times 10^7/squareroot 2 j^^+ 1.5 times 10^7/squareroot 2 k^^) times 0.44 i^^] = -0.747 times 10^-13 k^^- 0.747 times 10^-13 j^^N 0, -0.747 times 10^-13, -0.747 times 10^-13 N