During discharging the current decays as i = I*e^-(t/RC)
I = iniital current
C = capacitance = 3*10^-15 F
i = I/100
I/100 = I*e^-(t/(12*3*10^-15))
1/100 = e^-(t/(12*3*10^-15))
t = 1.66*10^-13 s <<-------answer
The is opened at a certain time. How much time does it take for the current...
9. Consider the RL circuit given in the figure. The switch is opened at time t = 0 after it had been closed for a long time. a) How long will it take for the current in the inductor to drop to 25% of its initial value? b) How long will it take for the energy in the inductor to drop to 25% of its initial value? Switch 200 unit of L my i 3150 80.5H BS 12 V
A certain reaction has a fixed half-life of 125 sec, how much time does it take for 25.0% of the original reactant to be reacted?
4. How much time does it take for light from the sun to reach the earth? (The distance between the sun and the earth is, on average, 1.50 x 10 m. The speed of light in vacuum is 3.00 x 10° m/s.) 5. You drop a 1.00-kg lead ball from a height of 2.50 meters. How much times does it take for the ball to hit the ground?
Starting from the uncharged state, how long does it take for
the current to drop from its initial value to 1.58mA?
Have to repost because first answer was incorrect.
Problem 26.45 Two 4.2 HF capacitors, two 2.3 k2resistors, and a 14.0 V source are connected in series.
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In the circuit shown in (Figure 1) switch Si has been closed a long time while switch S2 has been left open. Then S2 is closed at the same instant when S1 is opened.Part A Just after S2 is closed, the current through the resistor is 12.0 A and its rate of decrease is di/dt = 36.0 A/s. How long does it take the current to decrease to Figure 1 of 1 6.00 A, one-half its initial value?
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