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Question 10 0.59 pts What is the pH of a buffer made using 45.0 mL of 0.750 M HC2H5O2 (propanoic acid, K, = 1.3x10-5) and 55.
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If you think 700 M is correct then you can easily substitute 0.700 by 700 then you wont get the answer in given options but will get a value more than 7 which is not possible in case of acidic buffer. It should be less than 7 for acidic buffer at 25 degree CelsiusI think you have misprinted the malenty of Boddum propanoate & You have written toom It should be 0.700 According to given op* 1° Lh (не, и, о.) Р - sinie volume 5. me for both рка— -а 38:50 p = -log ka t lag | 33, 15 -3-2 | 134в) + 3 (141оти) 4.38

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