Question

From the information below calculate the percent yield. What is the limiting reagent? for nylon 6, 10

H2N(CH2)6NH2 + ClCO(CH2)8COCl --> -[-NH(CH2)6NHCO(CH2)8CO-]- +2HCl

regents used :

1,6-diaminohexane (1.1 g) and NaOH (1.0 g)

distilled water (30 mL,).

decanedioyl chloride (2.0 mL,)

dichloromethane (25 mL,).

The isolated product (1.50 g)

Answer 1

density of u Molar many of 1,6-diaminohexane= 116.21 g molt Molar man of decanedioyl chlon'de = 289.14gmont 112 g/cm3 = 112 g/mL ". Man of x volume density 21.12 g 2:24 g gor No. of moles of 1,6-diamino hexane- am wt. Molar maxx DI 11 mi x20mL и u 116.21 gm mott -0.0095 mol No. of moles of decane.droyl chlon'de 2.24% 0.0094 mol 289.14 gmoty " No. of moles of in less than 1,6-diaminohexane therefore decanedioyl chlon'de in limiting reactant. vo Imole of u yields Imole of nylon G, 10 i No. of moles of nylon 6, 10 = 0.0094 mol : Theoretical yield of nylon 6,10 = moles x molar man 0.00940not x 262.43 g mot 2.65 u - g X100 - yield of nylon G110 indulated field Theoretical yield 1.50x100 2,65 1) = 56.6%

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