At what temperature would a 1.40 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86 ∘C/m . Express your answer with the appropriate units.
At what temperature would a 1.40 m NaCl solution freeze, given that the van't Hoff factor...
5) At what temperature would a 1.55 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86 .C/m. The freezing point for pure water is 0.0 °C and Kf is equal to 1.86 °C/m.
Colligative properties, such as boiling point elevation, depend on the number of dissolved particles in solution. For nonelectrolytes, no dissociation occurs, and so you can use the number of moles of solute to calculate both molality and molarity. In contrast, electrolytes dissociate, and therefore the molality and molarity must be calculated based on the number of moles of dissociated particles or ions. There are two ions per formula unit of NaCl. Therefore, we would expect the freezing-point depression ΔTf of...
Freezing point depression can be used to experimentally determine the van't Hoff factor of a solute in solution. Given the data in the table, please answer the questions below and determine the "real" van't Hoff factor of the solute. Experimental Results Mass of solvent (water) Freezing point of water Freezing point depression constant (Kf) of water Mass of solution Freezing point of solution 8.515 g 0.00°C 1.86°C/m 9.3589 -5.45°C a. What mass of solute was used? b. What is the...
Calculate the osmotic pressure of a 0.0515 M NaCl solution at 25°C. (The van't Hoff factor for NaCl is 1.90)
You have a aqueous solution of NaCl that has a freezing point of -9.35°C. Assuming a van't Hoff factor of 1.9 for NaCl, what is the mass percent of chloride ion in the solution? (Kf for water is 1.86°C kg/mol).
what is the actual van't hoff factor for an aqueous 0.20 molal solution of FeCl3 if the freezing point is -1.2C? assume the Kf of water is 1.86C/m
For an aqueous solution of HF, determine the van't Hoff factor assuming 0% ionization. For the same solution, determine the van't Hoff factor assuming 100% ionization. A solution is made by dissolving 0.0300 mol HF in 1.00 kg of water. The solution was found to freeze at -0.0644°C. Calculate the value of i and estimate the percent ionization of HF in this solution.
[2.6] 6. a. Calculate the van't Hoff factor of a 0.085 M potassium sulfate solution that has an osmotic pressure of 5.4 atm at 25°C. b. Is this actual van't Hoff factor less than or greater than the ideal (expected) van't Hoff factor? Explain why the observed factor is different than the ideal factor.
A saline solution begins to freeze at -1.13°C. Express the concentration of NaCl in this solution in mass %. Kf for water is 1.86°C m-1. A.) .870% B.) 8.90% C.) 1.74% D.) 17.8% E.) 3.48% I need help with this problem!! :( & a question i have is if the "i" value is negative or not? please thoroughly explain each step, thank you!
Assume that the solubility of CaCl2 at this temperature is 70.1 g CaCl2/100.0 g of H2O and that the van't Hoff factor for a saturated solution of CaCl2 is i = 2.5. The Kf for water is 1.86°C/m What is the minimum amount of CaCl2 that would be required to melt ice on sidewalks at the above temperature- -33.0 degrees C? Use 100.0 g of water as the amount of solvent. Give your answer in grams.