Question

What is the OH ion concentration in a 4.8 x 10-2 M KOH solution? 2.1 x 10-13 M 4.8 x 10-2 M 1.0 x 10-7 M 4.8 x 10-12 M
What is E for the following balanced reaction? Fe(s) + Cu2+(aq) Fe2+ (aq) + Cu(s) Standard Reduction Potential Half-reaction
0 0
Add a comment Improve this question Transcribed image text
Answer #1

so And 0 since kot is strong base of lonized completely Кри у к+бна so concentration of (OH-] = 4.8x10² M so option (2) is co

Add a comment
Know the answer?
Add Answer to:
What is the OH ion concentration in a 4.8 x 10-2 M KOH solution? 2.1 x...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 9) What is the H+ ion concentration in a 4.8 x 10–2 M KOH solution? A)...

    9) What is the H+ ion concentration in a 4.8 x 10–2 M KOH solution? A) 4.8 x 10–2 M B) 1.0x 10–7 M C) 2.1 x10–13 M D) 4.8 x 10–11 M 10) HA is a weak acid. Which equilibrium corresponds to the equilibrium constant Kb for A-? A) HA (aq) + H2O (l) H2A+ (aq) + OH-(aq) B) A- (aq) + H3O+ (aq) C) HA (aq) + OH- (aq) H2O (l) + H+ (aq) HA (aq) + H2O...

  • 38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at...

    38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at the cathode and what is the Eceu? Fe2+(aq) + 2e → Fe(s) E°=-0.44 V Cu²+(aq) + 2e → Cu(s) E°= 0.34 V a) b) c) d) Cu2+(aq) + 2e → Cu(s), Ecell = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecel = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecell =-0.10 V Cu²+(aq) + 2e → Cu(s), Ecel = 0.10 V Cu²+ (aq) +...

  • 3. For the reaction below, what is the value of E when [Cu2+]-0.04 M and [Fe2+]=0.4...

    3. For the reaction below, what is the value of E when [Cu2+]-0.04 M and [Fe2+]=0.4 M? Cu(aq) + Fe(s)Cu(s) + Fe2 (aq) E +0.78 V 4. How many minutes are required to plate 2.08 g of Cu at a current of 1.26 A? Cu2 (aq) +2e Cu(s)

  • please show work and how they got the answer 13. If [Cu2+] = 0.30 M for...

    please show work and how they got the answer 13. If [Cu2+] = 0.30 M for the same cell described below, then what concentration of Fe2+ is needed to result in Ecell = 0.76 V? You will need to use the standard reduction potential table. Cu2+/ Cu → E = +0.34 V Fe2+/ Fe → E = -0.45 Cu?* (aq) + Fe(s) - Fe* (aq) + Cu(s) Eºcell = +0.78 V, Q = x/ 0.30, X = [Fe2+], Using Nernst,...

  • Find the best combination of half-cell pair from the following list, which will give the highest...

    Find the best combination of half-cell pair from the following list, which will give the highest voltage. What is the voltage for that Galvanic cell? Given that Reduction Half-reaction Standard Potential (Eredo)   Zn2+(aq) + 2e– → Zn(s) -0.763 (V) Fe2+(aq) + 2e– → Fe(s) -0.44 (V) Cu2+(aq) + 2e– → Cu(s) +0.34 (V) Sn2+(aq) + 2e– → Sn(s) -0.14 (V) Cu2+(aq) + e– → Cu+(aq) + 0.153 (V) Ag+(aq) + e– → Ag(s) + 0.80 (V)   Cu+(aq) + e– →...

  • What is the concentration of the Cu²⁺(aq) ion in a 0.015 M Cu(NO₃)₂ solution that is...

    What is the concentration of the Cu²⁺(aq) ion in a 0.015 M Cu(NO₃)₂ solution that is also 1.0 M NH₃? The Kf for Cu(NH₃)₄²⁺ = 4.8 x 10¹² .

  • I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help...

    I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help determine the chart. Please Show Work thank you so much An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...

  • QUESTION 8 Refer to the data you obtained in the simulation for the concentration cells. Select...

    QUESTION 8 Refer to the data you obtained in the simulation for the concentration cells. Select the correct statements that describe the concentration cell with half cells containing 0.01 M Cu2+ and 0.10 M Cu2+ respectively The voltage is 29.6 mV The voltage is 59.2 mV The solution containing 0.1 M Cu2+ is at the cathode The solution containing 1.0 M Cu2+ is at the cathode The solution containing 0.1 M Cu2+ is at the anode The solution containing 0.01...

  • ​What is the standard emf of a galvanic cell made of a Co electrode in a 1.0 M Co(NO32 solution and a Al electrode in a 1.0 M AI(NO3)3 solution at 25°C?

    What is the standard emf of a galvanic cell made of a Co electrode in a 1.0 M Co(NO32 solution and a Al electrode in a 1.0 M AI(NO3)3 solution at 25°C? 0 cell Standard Reduction Potentials at 25°C Half-Reaction E(V +2.87 +2.07 +1.82 O,(g) 2H (aq)2e0(g)+HO Co3+(aq) + e-_? Co2+(aq) H,02(aq) + 2H"(aq) + 2e-_ 2H20 Cu2+(aq) + 2e-? Cu(s) AgCIs) + Ag(s) + CI(a) S02-(aq) + 4H'(aq) + 2e S02(g) + 2H20 Cu2+(aq) + e-_ Cu+(aq) Sn (aq)...

  • Using the information in the table: Which combination of metals, if used to create an electrochemical...

    Using the information in the table: Which combination of metals, if used to create an electrochemical cell, would produce the largest voltage? Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e + Cu2+(aq) + 2e → Cu(s) Zn(s) + Cu2+ (aq) → Zn2+ (aq) + Cu(s) E half-cell = 0.7628 V Eºhalf-cell =...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT