Question

Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5 2.7 3.5 4.6 4.9 3.6 2.6 2.2 6.3 5.2 3.3 6.7 Which distribution should be used to construct the confidence interval? o A. Use a normal distribution because ơ is known and the data are normally distributed. o B. Use a t-distribution because n< 30 and ơ is unknown. ° C. Use a normal distribution because n< 30, the data are normaly distributed and σ is unknown. O D. Use a t-distribution because n< 30 and ơ is known. O E. Cannot use the standard normal distribution or the t-distribution because σ is unknown, n< 30, and the data are not normally distributed. Select the correct choice below and, if necessary, fill in any answer boxes to complete your choice. 0 A. The 99% confidence interval is (OD, Round to two decimal places as needed.) OB. Neither distribution can be used to construct the confidence interval Interpret the results. Choose the correct answer below. O A· B. ° C. lf a large sample of players are taken approximately 9996 of them will have yards per carry between the bounds Of the confidence interval. It can be said that 99% of players have a yards per carry between the bounds of the confidence interval. With 99% confidence, it can be said that the population mean yards per carry is between the bounds of the confidence interval. D. Neither distribution can be used to construct the confidence interval

Answer 1